Inductors

Q1: What is the maximum source current for a transformer rated at 10 kVA, 1000/500 60 Hz?

A 2 A

B 5 A

C 20 A

D 10 A

ANS:D - 20 A

1000/500 means that the voltage applied to the primary is 1000 Volt and so the secondary voltage is 500 Volt. If this is true, then the maximum current that you can deliver from the secondary is:

Vp = 1000.
Vs = 500.
(Apparent Power = V x I).
I = P/Vs.
I = 10 * 10^3 / 500,
I = 20 Amp.



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