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Declarations and Initializations

Q1:
What is the output of the program in Turbo C (in DOS 16-bit OS)? 
#include<stdio.h>
int main()
{
    char *s1;
    char far *s2;
    char huge *s3;
    printf('%d, %d, %d\n', sizeof(s1), sizeof(s2), sizeof(s3));
    return 0;
}

A 2, 4, 6

B 4, 4, 2

C 2, 4, 4

D 2, 2, 2

ANS:A - 2, 4, 6

Any pointer size is 2 bytes. (only 16-bit offset)
So, char *s1 = 2 bytes.
So, char far *s2; = 4 bytes.
So, char huge *s3; = 4 bytes.
A far, huge pointer has two parts: a 16-bit segment value and a 16-bit offset value. Since C is a compiler dependent language, it may give different output in other platforms. The above program works fine in Windows (TurboC), but error in Linux (GCC Compiler).



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