Signals and Switches

Q1:
What is the output voltage from the circuit in the given figure?

A +15 V

B 0 V

C +12 V

D +3 V

ANS:D - 0 V

Vce=Vcc-Ic*Rc.

When the tr. conduct(due to positive I/P or base-emitter voltage here CE config. ) the collector current increases and voltage drop across Rc increases which in turns decreases Vce bcz Vcc is fixed. That's why when input voltage is high then output voltage Vce is 0 i.e 0v.



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