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Inductors - Technical MCQs

Q1:

What is the phase angle between the source voltage and current, when a 100 mH inductor with a reactance of 6 komega.gif, and a 1 komega.gif resistor are in series with a source?

A 0.1 degrees

B 9.0 degrees

C 61.0 degrees

D 81.0 degrees

ANS:D - 81.0 degrees

tan θ = (XC/R) ==> θ = tan^(-1) (XC/R) ==> (Phase angle for SERIES RC Circuit)
tan θ = (R/XC) ==> θ = tan^(-1) (R/XC) ==> (Phase angle for PARALLEL RC Circuit)

tan θ = (XL/R) ==> θ = tan^(-1) (XL/R) ==>(Phase angle for SERIES RL Circuit)
tan θ = (R/XL) ==> θ = tan^(-1) (R/XL)) ==> (Phase angle for PARALLEL RL Circuit)

Given: L = 100 m H; XL = 6 kΩ, R = 1 k Ω, θ =?

tan θ = (XL/R) = θ = tan^(-1) (XL/R) ==>(Phase angle for SERIES RL Circuit)
tan θ = (XL/R) = θ = tan^(-1) (6 kΩ /1 kΩ) ==> tan^(-1) (6) = 80.53 -> 81.00 °.