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Magnetism and Electromagnetism

Q1:

What is the reluctance of a material that has a length of 0.045 m, a cross-sectional area of 0.015 m2, and a permeability of 2500 µWb/At·m?

A 833.33 µAt/Wb

B 0.27 At/Wb

C 1200 At/Wb

D More information is needed in order to find the reluctance.

ANS:C - 1200 At/Wb

Reluctance(R) = Length(l)/Permeability(µ)*Area(A).

R = 0.045/2500x10^-6 * 0.015

R = 1200.



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