RLC Circuits and Resonance

Q1:
What is the total current for the nonideal circuit in the given circuit. If it is at resonance?

A 0 A

B

284

A

C 3.3 mA

D 38.5 mA

ANS:A - 0 A

Convert the circuit to the equivalent practical circuit.

fr = 1/2π*√(LC) = 3.2kHz.
Rpractical = ((Rs^2)+(Xl^2)) / Rs = 17612.51 ohms,
since Xl = Xc at resonance,
Z = Rpractical,

Therefore;
5/ Rpractical = 283.88 micro ampere.

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