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Inductors

Q1:

What is the total inductance assuming no mutual inductance?

mcq8_1031_1.gif

A 0 mH

B 0.69 mH

C 12 mH

D 24 mH

ANS:B - 0.69 mH

Total inductance in parallel(LT)

1/LT=1/L1+1/L2+1/L3+1/L4
=(1/1+1/5+1/6+1/12)1/10^-3
=(1+0.2+0.1667+0.0175)10^3
1/LT=1.3842*10^3
LT=1/(1.3842*10^3)
=0.7224*10^-3
=0.72mH~~0.69mH
SO Ans is B.



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