Q1: What is the total inductance of a 5 H and a 100 mH coil connected in parallel?

A 4.76 mH

B 33.3 mH

C 98.0 mH

D 150.0 mH

ANS:C - 98.0 mH

LT = (L1* L2)/(L1 + L2).

L1 = 5H = 5000mH.
L2 = 100mH.

LT = (5000 * 100)/(5000 + 100).
LT = 98.03mH.
LT = 98Mh.

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