What is the total resistance of a circuit when R1 (7 k ) is in series with a parallel combination of R2 (20 k ), R3 (36 k ), and R4 (45 k )?-A-4 k B-17 k C-41 k D-108 k -B-17 k

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APTITUDE CRACK · Accepted Answer

The correct option is  B 17 k  Since parallel combination of resisitor is lees than least resistance . therefore parallel combination of 20 36 45 is less than 20. for this combination a series resistance of 7 is added .max answer is less than 20+7=27 there c and d options are not correct . a is also not correct because 7+anything is greater than 7. There fore the correct answer is 17 which is option B.

Series-Parallel Circuits

Q1: What is the total resistance of a circuit when R₁ (7 k ) is in series with a parallel combination of R₂ (20 k ), R₃ (36 k ), and R₄ (45 k )?

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Series-Parallel Circuits

Q1: What is the total resistance of a circuit when R1 (7 k ) is in series with a parallel combination of R2 (20 k ), R3 (36 k ), and R4 (45 k )?

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Q1: What is the total resistance of a circuit when R₁ (7 k ) is in series with a parallel combination of R₂ (20 k ), R₃ (36 k ), and R₄ (45 k )?

For help Students Orientation
Mcqs Questions