Capacitors

Q1: What is the value of a capacitor that can store two coulombs of charge when 500 volts is applied across its plates?

A 4 F

B 250 F

C 4,000 F

D 250 F

ANS:C - 4,000 F

Q=CV. SO C= Q/V. =2/500. 4*10^-3. = 4*10^3*10^-6. = 4000 micro farad.



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