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Capacitors - Technical MCQs

Q1:

What will a 1 F capacitor store?

A one coulomb of charge

B 6.24 x 1012 electrons

C one volt

D one A of current

ANS:B - 6.24 x 1012 electrons

One electron charge = 1.6*10^-19 coulombs, So one coulomb = 1/1.6*10^-19 electrons = 6.25*10^18 electrons. We know that q = c*v. One farad = one coulomb/one volt = one coluomb = 6.25*10^18 electrons. 1 microfarad = 6.25*10^18 *10^-6 = 6.24*10^12 electrons.