Q1: What will be the output of the program?

class BitShift 
{
    public static void main(String [] args) 
    {
        int x = 0x80000000;
        System.out.print(x + ' and  ');
        x = x >>> 31;
        System.out.println(x);
    }
}

ANS:A - -2147483648 and 1

Option A is correct. The >>> operator moves all bits to the right, zero filling the left bits. The bit transformation looks like this: Before: 1000 0000 0000 0000 0000 0000 0000 0000 After: 0000 0000 0000 0000 0000 0000 0000 0001 Option C is incorrect because the >>> operator zero fills the left bits, which in this case changes the sign of x, as shown. Option B is incorrect because the output method print() always displays integers in base 10. Option D is incorrect because this is the reverse order of the two output numbers.