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Operators and Assignments - Programming

Q1:

What will be the output of the program? 
class PassS 
{
    public static void main(String [] args) 
    {
        PassS p = new PassS();
        p.start();
    }

    void start() 
    {
        String s1 = 'slip';
        String s2 = fix(s1);
        System.out.println(s1 + ' ' + s2);
    }

    String fix(String s1) 
    {
        s1 = s1 + 'stream';
        System.out.print(s1 + ' ');
        return 'stream';
    }
}

A slip stream

B slipstream stream

C stream slip stream

D slipstream slip stream

ANS:A - slip stream

When the fix() method is first entered, start()'s s1 and fix()'s s1 reference variables both refer to the same String object (with a value of 'slip'). Fix()'s s1 is reassigned to a new object that is created when the concatenation occurs (this second String object has a value of 'slipstream'). When the program returns to start(), another String object is created, referred to by s2 and with a value of 'stream'.