Operators and Assignments - Programming

Q1:

What will be the output of the program?
class Two 
{
    byte x;
}

class PassO 
{
    public static void main(String [] args) 
    {
        PassO p = new PassO();
        p.start();
    }

    void start() 
    {
        Two t = new Two();
        System.out.print(t.x + ' ');
        Two t2 = fix(t);
        System.out.println(t.x + ' ' + t2.x);
    }

    Two fix(Two tt) 
    {
        tt.x = 42;
        return tt;
    }
}

A null null 42

B 0 0 42

C 0 42 42

D 0 0 0

ANS:A - null null 42

In the fix() method, the reference variable tt refers to the same object (class Two) as the t reference variable. Updating tt.x in the fix() method updates t.x (they are one in the same object). Remember also that the instance variable x in the Two class is initialized to 0.