What will be the output of the program, if a short int is 2 bytes wide?

#include<stdio.h>
int main()
{
    short int i = 0;
    for(i<=5 && i>=-1; ++i; i>0)
        printf('%u,', i);
    return 0;
}

for(i<=5 && i>=-1; ++i; i>0) so expression i<=5 && i>=-1 initializes for loop. expression ++i is the loop condition. expression i>0 is the increment expression. In for( i <= 5 && i >= -1; ++i; i>0) expression i<=5 && i>=-1 evaluates to one. Loop condition always get evaluated to true. Also at this point it increases i by one. An increment_expression i>0 has no effect on value of i.so for loop get executed till the limit of integer (ie. 65535)