

Arrays - Programming
Q1: What will be the output of the program if the array begins 1200 in memory?
#include<stdio.h>
int main()
{
int arr[]={2, 3, 4, 1, 6};
printf('%u, %u, %u\n', arr, &arr[0], &arr);
return 0;
}
A 1200, 1202, 1204
B 1200, 1200, 1200
C 1200, 1204, 1208
D 1200, 1202, 1200
ANS:A - 1200, 1202, 1204 Step 1: int arr[]={2, 3, 4, 1, 6}; The variable arr is declared as an integer array and initialized. Step 2: printf('%u, %u, %u\n', arr, &arr[0], &arr); Here, The base address of the array is 1200. => arr, &arr is pointing to the base address of the array arr. => &arr[0] is pointing to the address of the first element array arr. (ie. base address) Hence the output of the program is 1200, 1200, 1200 |


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