[Solved] What will be the output of the program in DOS (Compiler - Turbo C)? #include<stdio.h> double i; int main() { (int)(float)(char) i; printf('%d', sizeof((int)(float)(char)i)); return 0; } - Programming - C Programming - Complicated Declarations

Complicated Declarations

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What will be the output of the program in DOS (Compiler - Turbo C)?

#include<stdio.h>
double i;

int main()
{
    (int)(float)(char) i;
    printf('%d', sizeof((int)(float)(char)i));
    return 0;
}

A 1

B 2

C 4

D 8

ANS:A - 1

Due to the C language is being platform dependent:

In Turbo C (DOS - 16 bit platform), the output will be 2.

But in GCC (Unix/Linux - 32 bit platform), the output will be 4.

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Complicated Declarations

What will be the output of the program in DOS (Compiler - Turbo C)?
`#include<stdio.h> double i; int main() { (int)(float)(char) i; printf('%d', sizeof((int)(float)(char)i)); return 0; }`

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Complicated Declarations

What will be the output of the program in DOS (Compiler - Turbo C)? #include<stdio.h> double i; int main() { (int)(float)(char) i; printf('%d', sizeof((int)(float)(char)i)); return 0; }

Solution

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What will be the output of the program in DOS (Compiler - Turbo C)?
`#include<stdio.h> double i; int main() { (int)(float)(char) i; printf('%d', sizeof((int)(float)(char)i)); return 0; }`

For help Students Orientation
Mcqs Questions