[Solved] What will be the output of the program in Turb C (under DOS)? #include<stdio.h> int main() { int arr[5], i=0; while(i<5) arr[i]=++i; for(i=0; i<5; i++) printf('%d, ', arr[i]); return 0; } - Programming - C Programming - Arrays

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Q1: What will be the output of the program in Turb C (under DOS)?

#include<stdio.h>

int main()
{
    int arr[5], i=0;
    while(i<5)
        arr[i]=++i;

    for(i=0; i<5; i++)
        printf('%d, ', arr[i]);

    return 0;
}

A 1, 2, 3, 4, 5,

B Garbage value, 1, 2, 3, 4,

C 0, 1, 2, 3, 4,

D 2, 3, 4, 5, 6,

ANS:A - 1, 2, 3, 4, 5,

Since C is a compiler dependent language, it may give different outputs at different platforms. We have given the TurboC Compiler (Windows) output. Please try the above programs in Windows (Turbo-C Compiler) and Linux (GCC Compiler), you will understand the difference better.

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Q1: What will be the output of the program in Turb C (under DOS)?
`#include<stdio.h> int main() { int arr[5], i=0; while(i<5) arr[i]=++i; for(i=0; i<5; i++) printf('%d, ', arr[i]); return 0; }`

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Q1: What will be the output of the program in Turb C (under DOS)? #include<stdio.h> int main() { int arr[5], i=0; while(i<5) arr[i]=++i; for(i=0; i<5; i++) printf('%d, ', arr[i]); return 0; }

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Q1: What will be the output of the program in Turb C (under DOS)?
`#include<stdio.h> int main() { int arr[5], i=0; while(i<5) arr[i]=++i; for(i=0; i<5; i++) printf('%d, ', arr[i]); return 0; }`

For help Students Orientation
Mcqs Questions