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C Preprocessor - Programming

Q1:

What will be the output of the program? 
#include<stdio.h>
#define MIN(x, y) (x<y)? x : y;
int main()
{
    int x=3, y=4, z;
    z = MIN(x+y/2, y-1);
    if(z > 0)
        printf('%d\n', z);
    return 0;
}

A 3

B 4

C 0

D No output

ANS:A - 3

The macro MIN(x, y) (x<y)? x : y; returns the smallest value from the given two numbers. Step 1: int x=3, y=4, z; The variable x, y, z are declared as an integer type and the variable x, y are initialized to value 3, 4 respectively. Step 2: z = MIN(x+y/2, y-1); becomes, => z = (x+y/2 < y-1)? x+y/2 : y - 1; => z = (3+4/2 < 4-1)? 3+4/2 : 4 - 1; => z = (3+2 < 4-1)? 3+2 : 4 - 1; => z = (5 < 3)? 5 : 3; The macro return the number 3 and it is stored in the variable z. Step 3: if(z > 0) becomes if(3 > 0) here the if condition is satisfied. It executes the if block statements. Step 4: printf('%d\n', z);. It prints the value of variable z. Hence the output of the program is 3