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C Preprocessor - Programming

Q1:

What will be the output of the program? 
#include<stdio.h>
#define PRINT(int) printf("int=%d, ", int);

int main()
{
    int x=2, y=3, z=4;   
    PRINT(x);
    PRINT(y);
    PRINT(z);
    return 0;
}

A int=2, int=3, int=4

B int=2, int=2, int=2

C int=3, int=3, int=3

D int=4, int=4, int=4

ANS:A - int=2, int=3, int=4

The macro PRINT(int) print("%d,", int); prints the given variable value in an integer format. Step 1: int x=2, y=3, z=4; The variable x, y, z are declared as an integer type and initialized to 2, 3, 4 respectively. Step 2: PRINT(x); becomes printf("int=%d,",x). Hence it prints 'int=2'. Step 3: PRINT(y); becomes printf("int=%d,",y). Hence it prints 'int=3'. Step 4: PRINT(z); becomes printf("int=%d,",z). Hence it prints 'int=4'. Hence the output of the program is int=2, int=3, int=4.