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C Preprocessor

Q1:

What will be the output of the program? 
#include<stdio.h>
#define SQUARE(x) x*x

int main()
{
    float s=10, u=30, t=2, a;
    a = 2*(s-u*t)/SQUARE(t);
    printf('Result = %f', a);
    return 0;
}

A Result = -100.000000

B Result = -25.000000

C Result = 0.000000

D Result = 100.000000

ANS:A - Result = -100.000000

The macro function SQUARE(x) x*x calculate the square of the given number 'x'. (Eg: 102) Step 1: float s=10, u=30, t=2, a; Here the variable s, u, t, a are declared as an floating point type and the variable s, u, t are initialized to 10, 30, 2. Step 2: a = 2*(s-u*t)/SQUARE(t); becomes, => a = 2 * (10 - 30 * 2) / t * t; Here SQUARE(t) is replaced by macro to t*t . => a = 2 * (10 - 30 * 2) / 2 * 2; => a = 2 * (10 - 60) / 2 * 2; => a = 2 * (-50) / 2 * 2 ; => a = 2 * (-25) * 2 ; => a = (-50) * 2 ; => a = -100; Step 3: printf('Result=%f', a); It prints the value of variable 'a'. Hence the output of the program is -100



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