Q1: What will be the output of the program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int i=0;
    i++;
    if(i<=5)
    {
        printf("AptitudeCrack");
        exit(1);
        main();
    }
    return 0;
}

ANS:D - Prints "AptitudeCrack"

Step 1: int i=0; The variable i is declared as in integer type and initialized to '0'(zero). Step 2: i++; Here variable i is increemented by 1. Hence i becomes '1'(one). Step 3: if(i<=5) becomes if(1 <=5). Hence the if condition is satisfied and it enter into if block statements. Step 4: printf("AptitudeCrack"); It prints "AptitudeCrack". Step 5: exit(1); This exit statement terminates the program execution. Hence the output is "AptitudeCrack".