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Memory Allocation

Q1:
What will be the output of the program? 
#include<stdio.h>
#include<string.h>

int main()
{
    char *s;
    char *fun();
    s = fun();
    printf('%s\n', s);
    return 0;
}
char *fun()
{
    char buffer[30];
    strcpy(buffer, 'RAM');
    return (buffer);
}

A 0xffff

B Garbage value

C 0xffee

D Error

ANS:A - 0xffff

The output is unpredictable since buffer is an auto array and will die when the control go back to main. Thus s will be pointing to an array , which not exists.



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