

Pointers - Programming
Q1: What will be the output of the program ?
#include<stdio.h>
int *check(static int, static int);
int main()
{
int *c;
c = check(10, 20);
printf("%d\n", c);
return 0;
}
int *check(static int i, static int j)
{
int *p, *q;
p = &i;
q = &j;
if(i >= 45)
return (p);
else
return (q);
}
A 10
B 20
C Error: Non portable pointer conversion
D Error: cannot use static for function parameters
ANS:A - 10 No answer description is available. Let's discuss. |


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