What will be the output of the program?

#include<stdio.h>
int get();

int main()
{
    const int x = get();
    printf('%d', x);
    return 0;
}
int get()
{
    return 20;
}

Step 1: int get(); This is the function prototype for the funtion get(), it tells the compiler returns an integer value and accept no parameters. Step 2: const int x = get(); The constant variable x is declared as an integer data type and initialized with the value '20'. The function get() returns the value '20'. Step 3: printf('%d', x); It prints the value of the variable x. Hence the output of the program is '20'.