[Solved] What will be the output of the program ? #include<stdio.h> int main() { char str[7] = AptitudeCrack ; printf( %s\n , str); return 0; } - Programming - C Programming - Strings

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What will be the output of the program ?

#include<stdio.h>

int main()
{
    char str[7] = "AptitudeCrack";
    printf("%s\n", str);
    return 0;
}

A Error

B AptitudeCrack

C Cannot predict

D None of above

ANS:C - Cannot predict

Here str[] has declared as 7 character array and into a 8 character is stored. This will result in overwriting of the byte beyond 7 byte reserved for '\0'.

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Strings

What will be the output of the program ?
`#include<stdio.h> int main() { char str[7] = "AptitudeCrack"; printf("%s\n", str); return 0; }`

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What will be the output of the program ? #include<stdio.h> int main() { char str[7] = "AptitudeCrack"; printf("%s\n", str); return 0; }

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What will be the output of the program ?
`#include<stdio.h> int main() { char str[7] = "AptitudeCrack"; printf("%s\n", str); return 0; }`

For help Students Orientation
Mcqs Questions