Q1: What will be the output of the program ?

#include<stdio.h>

int main()
{
    char *names[] = { "Suresh", "Siva", "Sona", "Baiju", "Ritu"};
    int i;
    char *t;
    t = names[3];
    names[3] = names[4];
    names[4] = t;
    for(i=0; i<=4; i++)
        printf("%s,", names[i]);
    return 0;
}

ANS:B - Suresh, Siva, Sona, Ritu, Baiju

Step 1: char *names[] = { "Suresh", "Siva", "Sona", "Baiju", "Ritu"}; The variable names is declared as an pointer to a array of strings. Step 2: int i; The variable i is declared as an integer type. Step 3: char *t; The variable t is declared as pointer to a string. Step 4: t = names[3]; names[3] = names[4]; names[4] = t; These statements the swaps the 4 and 5 element of the array names. Step 5: for(i=0; i<=4; i++) printf("%s,", names[i]); These statement prints the all the value of the array names. Hence the output of the program is "Suresh, Siva, Sona, Ritu, Baiju".