[Solved] What will be the output of the program ? #include<stdio.h> int main() { static char mess[6][30] = { Don't walk in front of me... , I may not follow; , Don't walk behind me... , Just walk beside me... , And be my friend. }; printf( %c, %c\n , *(mess[2]+9), *(*(mess+2)+9)); return 0; } - Programming - C Programming - Strings

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What will be the output of the program ?

#include<stdio.h>

int main()
{
    static char mess[6][30] = {"Don't walk in front of me...", 
                               "I may not follow;", 
                               "Don't walk behind me...", 
                               "Just walk beside me...", 
                               "And be my friend." };

    printf("%c, %c\n", *(mess[2]+9), *(*(mess+2)+9));
    return 0;
}

A t, t

B k, k

C n, k

D m, f

ANS:B - k, k

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Strings

What will be the output of the program ?
`#include<stdio.h> int main() { static char mess[6][30] = {"Don't walk in front of me...", "I may not follow;", "Don't walk behind me...", "Just walk beside me...", "And be my friend." }; printf("%c, %c\n", (mess[2]+9), (*(mess+2)+9)); return 0; }`

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Strings

What will be the output of the program ? #include<stdio.h> int main() { static char mess[6][30] = {"Don't walk in front of me...", "I may not follow;", "Don't walk behind me...", "Just walk beside me...", "And be my friend." }; printf("%c, %c\n", *(mess[2]+9), *(*(mess+2)+9)); return 0; }

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What will be the output of the program ?
`#include<stdio.h> int main() { static char mess[6][30] = {"Don't walk in front of me...", "I may not follow;", "Don't walk behind me...", "Just walk beside me...", "And be my friend." }; printf("%c, %c\n", (mess[2]+9), (*(mess+2)+9)); return 0; }`

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