[Solved] What will be the output of the program ? #include<stdio.h> int main() { char str = AptitudeCrack ; printf( %s\n , str); return 0; } - Programming - C Programming - Strings

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Q1: What will be the output of the program ?

#include<stdio.h>

int main()
{
    char str = "AptitudeCrack";
    printf("%s\n", str);
    return 0;
}

A Error

B AptitudeCrack

C Base address of str

D No output

ANS:A - Error

The line char str = "AptitudeCrack"; generates "Non portable pointer conversion" error. To eliminate the error, we have to change the above line to char *str = "AptitudeCrack"; (or) char str[] = "AptitudeCrack"; Then it prints "AptitudeCrack".

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Strings

Q1: What will be the output of the program ?
`#include<stdio.h> int main() { char str = "AptitudeCrack"; printf("%s\n", str); return 0; }`

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Q1: What will be the output of the program ? #include<stdio.h> int main() { char str = "AptitudeCrack"; printf("%s\n", str); return 0; }

Solution

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Q1: What will be the output of the program ?
`#include<stdio.h> int main() { char str = "AptitudeCrack"; printf("%s\n", str); return 0; }`

For help Students Orientation
Mcqs Questions