

Strings - Programming
Q1: What will be the output of the program ?
#include<stdio.h>
int main()
{
char str = "AptitudeCrack";
printf("%s\n", str);
return 0;
}
A Error
B AptitudeCrack
C Base address of str
D No output
ANS:A - Error The line char str = "AptitudeCrack"; generates "Non portable pointer conversion" error. To eliminate the error, we have to change the above line to char *str = "AptitudeCrack"; (or) char str[] = "AptitudeCrack"; Then it prints "AptitudeCrack". |


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