Q1:

What will be the output of the program?

#include<stdio.h>

int main()
{
    int y=128;
    const int x=y;
    printf('%d\n', x);
    return 0;
}

Step 1: int y=128; The variable 'y' is declared as an integer type and initialized to value '128'. Step 2: const int x=y; The constant variable 'x' is declared as an integer and it is initialized with the variable 'y' value. Step 3: printf('%d\n', x); It prints the value of variable 'x'. Hence the output of the program is '128'