Const

Q1:
What will be the output of the program?
#include<stdio.h>

int main()
{
    const char *s = '';
    char str[] = 'Hello';
    s = str;
    while(*s)
        printf('%c', *s++);

    return 0;
}

A Error

B Hel

C Hello

D H

ANS:A - Error

Step 1: const char *s = ''; The constant variable s is declared as an pointer to an array of characters type and initialized with an empty string. Step 2: char str[] = 'Hello'; The variable str is declared as an array of charactrers type and initialized with a string 'Hello'. Step 3: s = str; The value of the variable str is assigned to the variable s. Therefore str contains the text 'Hello'. Step 4: while(*s){ printf('%c', *s++); } Here the while loop got executed untill the value of the variable s is available and it prints the each character of the variable s. Hence the output of the program is 'Hello'.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.