What will be the output of the program?

int main()
    const char *s = '';
    char str[] = 'Hello';
    s = str;
        printf('%c', *s++);

    return 0;

A Error

B Hel

C Hello


ANS:A - Error

Step 1: const char *s = ''; The constant variable s is declared as an pointer to an array of characters type and initialized with an empty string. Step 2: char str[] = 'Hello'; The variable str is declared as an array of charactrers type and initialized with a string 'Hello'. Step 3: s = str; The value of the variable str is assigned to the variable s. Therefore str contains the text 'Hello'. Step 4: while(*s){ printf('%c', *s++); } Here the while loop got executed untill the value of the variable s is available and it prints the each character of the variable s. Hence the output of the program is 'Hello'.

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