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Control Instructions - Programming

Q1:

What will be the output of the program? 
#include<stdio.h>
int main()
{
    unsigned int i = 65536; /* Assume 2 byte integer*/
    while(i != 0)
        printf('%d',++i);
    printf('\n');
    return 0;
}

A Infinite loop

B 0 1 2 ... 65535

C 0 1 2 ... 32767 - 32766 -32765 -1 0

D No output

ANS:A - Infinite loop

Here unsigned int size is 2 bytes. It varies from 0,1,2,3, ... to 65535. Step 1:unsigned int i = 65536; here variable i becomes '0'(zero). because unsigned int varies from 0 to 65535. Step 2: while(i != 0) this statement becomes while(0 != 0). Hence the while(FALSE) condition is not satisfied. So, the inside the statements of while loop will not get executed. Hence there is no output. Note: Don't forget that the size of int should be 2 bytes. If you run the above program in GCC it may run infinite loop, because in Linux platform the size of the integer is 4 bytes.