- Control Instructions - General Questions
- Control Instructions - Find Output of Program
- Control Instructions - Point Out Errors
- Control Instructions - Point Out Correct Statements
- Control Instructions - True / False Questions
- Control Instructions - Yes / No Questions


Control Instructions - Programming
Q1: What will be the output of the program?
#include<stdio.h>
int main()
{
int a=0, b=1, c=3;
*((a) ? &b : &a) = a ? b : c;
printf('%d, %d, %d\n', a, b, c);
return 0;
}
A 0, 1, 3
B 1, 2, 3
C 3, 1, 3
D 1, 3, 1
ANS:A - 0, 1, 3 Step 1: int a=0, b=1, c=3; here variable a, b, and c are declared as integer type and initialized to 0, 1, 3 respectively. Step 2: *((a) ? &b : &a) = a ? b : c; The right side of the expression(a?b:c) becomes (0?1:3). Hence it return the value '3'. The left side of the expression *((a) ? &b : &a) becomes *((0) ? &b : &a). Hence this contains the address of the variable a *(&a). Step 3: *((a) ? &b : &a) = a ? b : c; Finally this statement becomes *(&a)=3. Hence the variable a has the value '3'. Step 4: printf('%d, %d, %d\n', a, b, c); It prints '3, 1, 3'. |


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