Q1: What will be the output of the program?

#include<stdio.h>
int main()
{
    int i=4;
    switch(i)
    {
        default:
           printf('This is default\n');
        case 1:
           printf('This is case 1\n');
           break;
        case 2:
           printf('This is case 2\n');
           break;
        case 3:
           printf('This is case 3\n');
    }
    return 0;
}

In the very begining of switch-case statement default statement is encountered. So, it prints 'This is default'. In default statement there is no break; statement is included. So it prints the case 1 statements. 'This is case 1'. Then the break; statement is encountered. Hence the program exits from the switch-case block.