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Exceptions - Programming

Q1:

What will be the output of the program? 
public class RTExcept 
{
    public static void throwit () 
    {
        System.out.print('throwit ');
        throw new RuntimeException();
    }
    public static void main(String [] args) 
    {
        try 
        {
            System.out.print('hello ');
            throwit();
        }
        catch (Exception re ) 
        {
            System.out.print('caught ');
        }
        finally 
        {
            System.out.print('finally ');
        }
        System.out.println('after ');
    }
}

A hello throwit caught

B Compilation fails

C
hello throwit RuntimeException caught after

D hello throwit caught finally after

ANS:A - hello throwit caught

The main() method properly catches and handles the RuntimeException in the catch block, finally runs (as it always does), and then the code returns to normal. A, B and C are incorrect based on the program logic described above. Remember that properly handled exceptions do not cause the program to stop executing.