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Declarations and Access Control

Q1:

What will be the output of the program? 
public class Test 
{
    public int aMethod()
    {
        static int i = 0;
        i++;
        return i;
    }
    public static void main(String args[])
    {
        Test test = new Test();
        test.aMethod();
        int j = test.aMethod();
        System.out.println(j);
    }
}

A 0

B 1

C 2

D Compilation fails.

ANS:A - 0

Compilation failed because static was an illegal start of expression - method variables do not have a modifier (they are always considered local).



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