[Solved] What will be the output of the program? public class Test { public static void main(String args[]) { int i = 1, j = 0; switch(i) { case 2: j += 6; case 4: j += 1; default: j += 2; case 0: j += 4; } System.out.println( j = + j); } } - Programming - Java Programming - Flow Control

Flow Control

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Flow Control - Finding the output

What will be the output of the program?

public class Test 
{  
    public static void main(String args[]) 
    { 
        int i = 1, j = 0; 
        switch(i) 
        { 
            case 2: j += 6; 
            case 4: j += 1; 
            default: j += 2; 
            case 0: j += 4; 
        } 
        System.out.println("j = " + j); 
    } 
}

A j = 0

B j = 2

C j = 4

D j = 6

ANS:D - j = 6

Because there are no break statements, the program gets to the default case and adds 2 to j, then goes to case 0 and adds 4 to the new j. The result is j = 6.

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Flow Control

What will be the output of the program?
`public class Test { public static void main(String args[]) { int i = 1, j = 0; switch(i) { case 2: j += 6; case 4: j += 1; default: j += 2; case 0: j += 4; } System.out.println("j = " + j); } }`

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Flow Control

What will be the output of the program? public class Test { public static void main(String args[]) { int i = 1, j = 0; switch(i) { case 2: j += 6; case 4: j += 1; default: j += 2; case 0: j += 4; } System.out.println("j = " + j); } }

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What will be the output of the program?
`public class Test { public static void main(String args[]) { int i = 1, j = 0; switch(i) { case 2: j += 6; case 4: j += 1; default: j += 2; case 0: j += 4; } System.out.println("j = " + j); } }`

For help Students Orientation
Mcqs Questions