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Threads - Programming

Q1:

What will be the output of the program? 
public class WaitTest 
{
    public static void main(String [] args) 
    {
        System.out.print('1 ');
        synchronized(args)
        {
            System.out.print('2 ');
            try 
            {
                    args.wait(); /* Line 11 */
            }
            catch(InterruptedException e){ }
        }
        System.out.print('3 ');
    }
}

A
It fails to compile because the IllegalMonitorStateException of wait() is not dealt with in line 11.

B 1 2 3

C 1 3

D 1 2

ANS:A -

It fails to compile because the IllegalMonitorStateException of wait() is not dealt with in line 11.

1 and 2 will be printed, but there will be no return from the wait call because no other thread will notify the main thread, so 3 will never be printed. The program is essentially frozen at line 11. A is incorrect; IllegalMonitorStateException is an unchecked exception so it doesn't have to be dealt with explicitly. B and C are incorrect; 3 will never be printed, since this program will never terminate because it will wait forever.