[Solved] What will the SWAP macro in the following program be expanded to on preprocessing? will the code compile? #include<stdio.h> #define SWAP(a, b, c)(c t; t=a, a=b, b=t) int main() { int x=10, y=20; SWAP(x, y, int); printf('%d %d\n', x, y); return 0; } - Programming - C Programming - C Preprocessor

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Q1: What will the SWAP macro in the following program be expanded to on preprocessing? will the code compile?

#include<stdio.h>
#define SWAP(a, b, c)(c t; t=a, a=b, b=t)
int main()
{
    int x=10, y=20;
    SWAP(x, y, int);
    printf('%d %d\n', x, y);
    return 0;
}

A It compiles

B Compiles with an warning

C Not compile

D Compiles and print nothing

ANS:A - It compiles

The code won't compile since declaration of t cannot occur within parenthesis.

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C Preprocessor

Q1: What will the SWAP macro in the following program be expanded to on preprocessing? will the code compile?
`#include<stdio.h> #define SWAP(a, b, c)(c t; t=a, a=b, b=t) int main() { int x=10, y=20; SWAP(x, y, int); printf('%d %d\n', x, y); return 0; }`

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C Preprocessor

Q1: What will the SWAP macro in the following program be expanded to on preprocessing? will the code compile? #include<stdio.h> #define SWAP(a, b, c)(c t; t=a, a=b, b=t) int main() { int x=10, y=20; SWAP(x, y, int); printf('%d %d\n', x, y); return 0; }

Solution

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Q1: What will the SWAP macro in the following program be expanded to on preprocessing? will the code compile?
`#include<stdio.h> #define SWAP(a, b, c)(c t; t=a, a=b, b=t) int main() { int x=10, y=20; SWAP(x, y, int); printf('%d %d\n', x, y); return 0; }`

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