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Series-Parallel Circuits

Q1: When a load resistance is removed from the output of a voltage divider circuit, the current drawn from the source

A decreases

B increases

C remains the same

D is cut off

ANS:A - decreases

Assume a voltage source of 5V.
R1 = 10k ohms.
R(load) = 10k ohms.
Note that the load resistor is connected parallel to R1.

Rtotal = (10k*10k)/(10k + 10k) = 5k ohms,
I = 5V/5k ohms = 1mA

Removing Rload
I = 5V/10k ohms = 0.5mA.
Thus, indicating that removing Rload will results in decreasing the current from the source.



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