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Ohm''s Law - Engineering

Q1:

When there is 12 mA of current through a 1.2 k resistor, the voltage across the resistor is

A 14.4 V

B 1.4 V

C 100 V

D 10 V

ANS:A - 14.4 V

V = IR (Ohms Law) = 12 X 10-3 X 1.2 X 10 3 = 12 X 1.2 = 14.4 V