- Chemical Engineering Basics - Section 1
- Chemical Engineering Basics - Section 2
- Chemical Engineering Basics - Section 3
- Chemical Engineering Basics - Section 4
- Chemical Engineering Basics - Section 5
- Chemical Engineering Basics - Section 6
- Chemical Engineering Basics - Section 7
- Chemical Engineering Basics - Section 8
- Chemical Engineering Basics - Section 9
- Chemical Engineering Basics - Section 10
- Chemical Engineering Basics - Section 11
- Chemical Engineering Basics - Section 12
- Chemical Engineering Basics - Section 13
- Chemical Engineering Basics - Section 14
- Chemical Engineering Basics - Section 15
- Chemical Engineering Basics - Section 16
- Chemical Engineering Basics - Section 17
- Chemical Engineering Basics - Section 18
- Chemical Engineering Basics - Section 19
- Chemical Engineering Basics - Section 20
- Chemical Engineering Basics - Section 21
- Chemical Engineering Basics - Section 22
- Chemical Engineering Basics - Section 23
- Chemical Engineering Basics - Section 24
- Chemical Engineering Basics - Section 25
- Chemical Engineering Basics - Section 26
- Chemical Engineering Basics - Section 27
- Chemical Engineering Basics - Section 28


Chemical Engineering Basics - Engineering
Q1: Which of the following pairs regarding the effect of alloying elements in steels are not matched correctly ?A Cobalt: It contributes to rerl hardness by hardening ferrite.
B Molybdenum: It forms abrasion resisting particles.
C Phosphorous: It improves machinability in free cutting steels.
D Silicon: It reduces oxidation resistance.
ANS:A - Cobalt: It contributes to rerl hardness by hardening ferrite. Cobalt is often used as an alloying element in steel, primarily in the production of high-speed steels and certain tool steels. The statement "Cobalt: It contributes to real hardness by hardening ferrite" suggests that cobalt contributes to the hardness of steel by hardening ferrite, a phase in the steel microstructure. Explanation:
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