Signals and Systems
A y[n] = x[2n]
B y[n] = x[n] x[n - 1]
C y[n] = x[n/2]
D all
ANS:B - y[n] = x[n] x[n - 1]
For time invariant system
y(n, k) = y(n - k), where y(n, k) mean shift the input by n - k, while y(n - k) mean change all the n
(a) y[n] = x[2n]
⇒ y(n, k) = x[2n - k]
y(n - k) = x[2(n - k)]
y(n, k) ≠ y(n - k) Time variant
(b) y[n] = x[n] x[n - 1]
y[n, k] = x[n - k] x[n - k - 1]
y[n - k] = x[n - k] x[n - k - 1]
y[n, k] = x[n - k] Time Invariant
(c) y[n] = x[n/2] ⇒ y[n, k] 
⇒ y[n - k] 
y[n, k] ≠ y[n - k] Time variant.
Share : |
For help Students Orientation
Mcqs Questions
One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.