Signals and Systems - Engineering

Q1:

Which one is time invariant system?

A y[n] = x[2n]

B y[n] = x[nx[n - 1]

C y[n] = x[n/2]

D all

ANS:B - y[n] = x[nx[n - 1]

For time invariant system y(n, k) = y(n - k), where y(n, k) mean shift the input by n - k, while y(n - k) mean change all the n (a) y[n] = x[2n] ⇒ y(n, k) = x[2n - k] y(n - k) = x[2(n - k)] y(n, k) ≠ y(n - k) Time variant (b) y[n] = x[n] x[n - 1] y[n, k] = x[n - k] x[n - k - 1] y[n - k] = x[n - k] x[n - k - 1] y[n, k] = x[n - k] Time Invariant (c) y[n] = x[n/2] ⇒ y[n, k] y[n - k] y[n, k] ≠ y[n - k] Time variant.