Q1: With 6 V applied, what is the voltage across R₂ of a parallel combination of R₂ (1 k ), R₃ (2 k ), and R₄ (1 k ) in series with R₁, whose value is 2 k ?

ANS:A - 1 V

R2=R2||R3||R4
=2/4 K ohm.
Total resistance = R1+R2
= 2 + 2/4 = 10/4 K ohm.

Using potential divider rule,
o/p V = (total vol x opp branch resistance)/total resistance.
V = (6*(2/4))/(10/4).
= 1 V.