With an RL integrator, at the instant of the rising pulse edge,

ANS:B - all the input voltage is across the inductor

Because just before the instant of rising pulse voltage capacitor was acting as a short ckt, and according to inductor property it will not allow sudden changes hence just after or at the instant of rising pulse voltage it remains in open circuit hence all the input voltage appears across the open circuit or across the inductor.

After a long time as inductor keeps on charging when it reaches steady state it will act as a short circuit and all the input voltage appears across the resistor.