Networks Analysis and Synthesis

Q1:
Z(c) for the network shown in the figure is The value of C and R are, respectively

A 1/6 F and 4 Ω

B 2/9 F and 9/2 Ω

C 2/3 F and 1/2 Ω

D 1/2 F and 1 Ω

ANS:A - 1/6 F and 4 Ω

Z(0) = 8.
2 resistance sum = 4 So, 8-4 = 4(R value).
1 capacitor sum = 1/2 so, 1/(8-(1/1/2)) (C value).

Here for capacitance, we use 1/c.

I don't know whether it's correct or not.



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