Communication Systems

Q1:
A superheterodyne receiver is to operate in the frequency range 550 kHz - 1650 kHz, with the intermediate frequency of 450 kHz. Let denote the required capacitance ratio of the local oscillator and I denote the image frequency (in kHz) of the incoming signal. If the receiver is tuned to 700 kHz, then

A R = 4.41 J =1600

B R = 2.10 J =1150

C R = 3.0 J =1600

D R = 9.0 J =1150

ANS:A - R = 4.41 J =1600

Image frequency = 700 + 2 x 450 1600 kHz fmax = 1650 + 450 2100 kHz fmin = 550 kHz + 450 1000 kHz R = 4.41, I = 1600 kHz.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.