An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank, and g = Acceleration due to gravity)-A-tan θ = a/gB-tan θ = 2 a/gC-tan θ = a/2gD-tan θ = a2/2g-A-tan θ = a/g

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An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank, and g = Acceleration due to gravity)-A-tan &theta; = a/gB-tan &theta; = 2 a/gC-tan &theta; = a/2gD-tan &theta; = a2/2g-A-tan &theta; = a/g

APTITUDE CRACK · Accepted Answer

A tan &theta; = a/g Explanation: No answer description is available.

Hydraulics and Fluid Mechanics - Engineering

An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank, and g = Acceleration due to gravity)

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Hydraulics and Fluid Mechanics - Engineering

An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank, and g = Acceleration due to gravity)

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