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Communication Systems - Engineering

Q1:

An oscillator at 4.2 MHz is followed by two frequency doublers and two triplers. The output frequency will be

A 84 MHz

B 112.4 MHz

C 151.2 MHz

D 303.4 MHz

ANS:C - 151.2 MHz

2^2*3^2*4.2.

i.e. 4*9*4.2.
or 36*4.2 = 151.2.