Applying DeMorgan's theorem to the expression , we get ________-A-B-C-D--A-

Question

Applying DeMorgan&#39;s theorem to the expression , we get ________-A-B-C-D--A-

APTITUDE CRACK · Accepted Answer

The correct option is  A  [(x+y)&#39;+z&#39;]&#39; (x+y)&#39;&#39;.(z)&#39;&#39; therefore we get (x+y).z

Boolean Algebra and Logic Simplification